x^2+200x-8000=0

Solution for x^2+200x-8000=0 equation:

x^2+200x-8000=0

a = 1; b = 200; c = -8000;
Δ = b2-4ac
Δ = 2002-4·1·(-8000)
Δ = 72000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72000}=\sqrt{14400*5}=\sqrt{14400}*\sqrt{5}=120\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-120\sqrt{5}}{2*1}=\frac{-200-120\sqrt{5}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+120\sqrt{5}}{2*1}=\frac{-200+120\sqrt{5}}{2}
$